Submission #3691359
Source Code Expand
def inpl(): return [int(i) for i in input().split()] import math X, Y = inpl() print(1+int(math.log2(Y/X)//1))
Submission Info
Submission Time | |
---|---|
Task | C - Multiple Gift |
User | Tallfall |
Language | Python (3.4.3) |
Score | 0 |
Code Size | 113 Byte |
Status | WA |
Exec Time | 19 ms |
Memory | 3060 KB |
Judge Result
Set Name | Sample | All | ||||||
---|---|---|---|---|---|---|---|---|
Score / Max Score | 0 / 0 | 0 / 300 | ||||||
Status |
|
|
Set Name | Test Cases |
---|---|
Sample | s1.txt, s2.txt, s3.txt |
All | 01.txt, 02.txt, 03.txt, 04.txt, 05.txt, 06.txt, 07.txt, 08.txt, 09.txt, 10.txt, 11.txt, 12.txt, s1.txt, s2.txt, s3.txt |
Case Name | Status | Exec Time | Memory |
---|---|---|---|
01.txt | AC | 19 ms | 3060 KB |
02.txt | AC | 18 ms | 2940 KB |
03.txt | AC | 18 ms | 2940 KB |
04.txt | AC | 18 ms | 2940 KB |
05.txt | AC | 18 ms | 2940 KB |
06.txt | WA | 18 ms | 2940 KB |
07.txt | AC | 18 ms | 2940 KB |
08.txt | AC | 18 ms | 2940 KB |
09.txt | AC | 18 ms | 2940 KB |
10.txt | AC | 18 ms | 2940 KB |
11.txt | AC | 18 ms | 2940 KB |
12.txt | AC | 17 ms | 2940 KB |
s1.txt | AC | 18 ms | 2940 KB |
s2.txt | AC | 18 ms | 2940 KB |
s3.txt | AC | 18 ms | 2940 KB |